X^2+6x-2040=0

Solution for X^2+6x-2040=0 equation:

X^2+6X-2040=0

a = 1; b = 6; c = -2040;
Δ = b2-4ac
Δ = 62-4·1·(-2040)
Δ = 8196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8196}=\sqrt{4*2049}=\sqrt{4}*\sqrt{2049}=2\sqrt{2049}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{2049}}{2*1}=\frac{-6-2\sqrt{2049}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{2049}}{2*1}=\frac{-6+2\sqrt{2049}}{2}
$